2/x+3+3/x+4=7/x^2+7x+12

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Solution for 2/x+3+3/x+4=7/x^2+7x+12 equation: 



2/x+3+3/x+4=7/x^2+7x+12

We move all terms to the left:

2/x+3+3/x+4-(7/x^2+7x+12)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: x^2+7x+12)!=0

x∈R



We add all the numbers together, and all the variables

2/x+3/x-(7/x^2+7x+12)+7=0

We get rid of parentheses

2/x+3/x-7/x^2-7x-12+7=0

We calculate fractions

We do not support expression: x^3

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